Ta có \(\dfrac{-49}{78}\)và\(\dfrac{-64}{95}\)
\(\dfrac{-49}{78}\)\(=\dfrac{-49.95}{78.95}=\dfrac{-4655}{7410}\)
\(\dfrac{-64}{95}=\dfrac{-64.78}{95.78}=\dfrac{-4992}{7410}\)
Vì -4655 > -4992 \(=>\dfrac{-4655}{7410}>\dfrac{-4992}{7410}\)
\(=>\dfrac{-49}{78}>\dfrac{64}{-95}\)