a)Ta có:
\(\frac{1212}{1313}=\frac{12\cdot101}{13\cdot101}=\frac{12}{13}\)
Suy ra \(\frac{12}{13}=\frac{1212}{1313}\)
câu b lạ
a)
Ta có
\(\frac{12}{13}=\frac{12.101}{13.101}=\frac{1212}{1313}\)
\(\Rightarrow\frac{12}{13}=\frac{1212}{1313}\)
b)
Ta có
\(1-\frac{123}{124}=\frac{1}{124}\)
\(1-\frac{124}{125}=\frac{1}{125}\)
Mà \(\frac{1}{124}>\frac{1}{125}\)
\(\Rightarrow1-\frac{123}{124}>1-\frac{124}{125}\)
\(\Rightarrow\frac{123}{124}< \frac{124}{125}\)
\(\Rightarrow\frac{123}{124}< \frac{124.1001}{125.1001}\)
\(\Rightarrow\frac{123}{124}< \frac{124124}{125125}\)
\(\frac{12}{13}và\frac{1212}{1212}\)
\(\frac{1212}{1313}=\frac{12.101}{13.101}\) \(\Rightarrow\) \(\frac{12}{13}\)
Mà \(\frac{12}{13}=\frac{12}{13}\) \(\Rightarrow\) \(\frac{12}{13}=\frac{1212}{1313}\)
\(\frac{123}{124}\) và \(\frac{124124}{125125}\)
\(1-\frac{123}{124}\) = \(\frac{1}{124}\)
\(1-\frac{124124}{125125}\) = \(\frac{1}{125}\)
Mà \(\frac{1}{124}>\frac{1}{125}\)
\(\Rightarrow\) \(1-\frac{123}{124}\) > \(1-\frac{124}{125}\)
\(\Rightarrow\) \(\frac{123}{124}\) <\(\frac{124}{125}\) \(\Rightarrow\) \(\frac{123}{124}\) < \(\frac{124.1001}{125.1001}\)
\(\Rightarrow\) \(\frac{123}{124}< \frac{124124}{125125}\)
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