Question

Sắp sếp các phân số sau theo thứ tự tăng dần

          \(\frac{105}{202};\frac{107}{206};\frac{109}{210};\frac{111}{214}\)

Answer 1

Có: \(\frac{105}{202}=\frac{101}{201}+\frac{4}{202}=\frac{1}{2}+\frac{2}{101}\)

      \(\frac{107}{202}=\frac{103}{202}+\frac{4}{202}=\frac{1}{2}+\frac{2}{103}\)

       \(\frac{109}{210}=\frac{105}{210}+\frac{4}{210}=\frac{1}{2}+\frac{2}{105}\)

        \(\frac{111}{214}=\frac{107}{214}+\frac{4}{214}=\frac{1}{2}+\frac{2}{107}\)

Vì:\(\frac{2}{107}< \frac{2}{105}< \frac{2}{103}< \frac{2}{101}\)

 Vậy:\(\frac{111}{214}< \frac{109}{210}< \frac{107}{206}< \frac{105}{202}\)