đk : x >= 0 ; x khác 1
\(P=\left(\dfrac{x-2+\sqrt{x}}{\sqrt{x}\left(\sqrt{x}+2\right)}\right).\dfrac{\sqrt{x}+1}{\sqrt{x}-1}=\dfrac{\left(x-1\right)\left(\sqrt{x}+2\right)}{\sqrt{x}\left(\sqrt{x}-1\right)\left(\sqrt{x}+2\right)}=\dfrac{\sqrt{x}+1}{\sqrt{x}}\)