Question

Rút gọn: \(P=\frac{\sqrt{x}+1}{x\sqrt{x}+x+\sqrt{x}}:\frac{1}{x^2-\sqrt{x}}\)

Answer 1

\(P=\frac{\sqrt{x}+1}{x\sqrt{x}+x+\sqrt{x}}:\frac{1}{x^2-\sqrt{x}}ĐKXĐ:x\ge0\)

\(=\frac{\sqrt{x}+1}{\sqrt{x}\left(x+\sqrt{x}+1\right)}.\frac{\sqrt{x}\left[\left(\sqrt{x}\right)^3-1\right]}{1}\)

\(=\frac{\left(\sqrt{x}+1\right).\left(\sqrt{x}-1\right)\left(x+\sqrt{x}+1\right)}{x+\sqrt{x}+1}\)

\(=x-1\)

Answer 2

ĐKXĐ mình bị nhầm nha :V

ĐKXĐ: x > 0; x ≠ 1