\(F=\left(\frac{3+\sqrt{5}}{\left(3+\sqrt{5}\right)\left(3-\sqrt{5}\right)}-\frac{3-\sqrt{5}}{\left(3+\sqrt{5}\right)\left(3-\sqrt{5}\right)}\right):\frac{\sqrt{5}\left(\sqrt{5}-1\right)}{\sqrt{5}-1}\)
\(=\left(\frac{3+\sqrt{5}-3+\sqrt{5}}{4}\right):\sqrt{5}=\frac{2\sqrt{5}}{4\sqrt{5}}=\frac{1}{2}\)