Hơi muộn :D
\(F^3=\)\(2+\sqrt{5}+2-\sqrt{5}+3.\sqrt[3]{-1}.F\)
⇔ \(F^3+3F-4=0\)
⇔ \(F^3-F^2+F^2-F+4F-4=0\)
⇔ \(\left(F-1\right)\left(F^2+F+4\right)=0\)
⇔ \(F=1\)
\(G=\sqrt[3]{1+3\sqrt[3]{2}+3\sqrt[3]{4}+2}=\sqrt[3]{\left(1+\sqrt[3]{2}\right)^3}\)
⇔ \(G=1+\sqrt[3]{2}\)