Question

Rút gọn

\(A=\frac{\sqrt{x}}{\sqrt{x}-2}+\frac{\sqrt{x}-1}{\sqrt{x}+2}+\frac{\sqrt{x}-10}{x-4}\) (x\(\ge\)0, x \(\ne\) 4)

\(B=\left(13-4\sqrt{3}\right)\left(7+4\sqrt{3}\right)-8\sqrt{20+2\sqrt{43+24\sqrt{3}}}\)

Answer 1

\(A=\frac{\sqrt{x}\left(\sqrt{x}+2\right)}{x-4}+\frac{\left(\sqrt{x}-1\right)\left(\sqrt{x}-2\right)}{x-4}+\frac{\sqrt{x}-10}{x-4}\)

\(A=\frac{x+2\sqrt{x}+x-3\sqrt{x}+2+\sqrt{x}-10}{x-4}\)

\(A=\frac{2x-8}{x-4}=\frac{2\left(x-4\right)}{x-4}=2\)

\(B=\left(13-4\sqrt{3}\right)\left(7+4\sqrt{3}\right)-8\sqrt{20+2\sqrt{\left(3\sqrt{3}+4\right)^2}}\)

\(B=43+24\sqrt{3}-8\sqrt{20+6\sqrt{3}+8}\)

\(B=43+24\sqrt{3}-8\sqrt{28+6\sqrt{3}}\)

\(B=43+24\sqrt{3}-8\sqrt{\left(3\sqrt{3}+1\right)^2}\)

\(B=43+24\sqrt{3}-24\sqrt{3}-8\)

\(B=35\)

Answer 2

Nguyễn Việt Lâm giúp mk nhá, tks bn nhìu :>>