\(\left(3\frac{16}{99}+4\frac{11}{99}-5\frac{8}{299}\right).\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
= \(\left(3\frac{16}{99}+4\frac{11}{99}-5\frac{8}{299}\right).\left(\frac{3}{6}-\frac{2}{6}-\frac{1}{6}\right)\)
= \(\left(3\frac{16}{99}+4\frac{11}{99}-5\frac{8}{299}\right).0\)
= 0
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