Question

Phân tích đa thức sau thành nhân tử: 

M=(a^2+b^2-c^2)^2 - 4a^2b^2

Answer 1

\(M=\left(a^2+b^2-c^2\right)^2-4a^2b^2\)

\(M=\left(a^2+b^2-c^2\right)^2-\left(2ab\right)^2\)

\(M=\left(a^2+b^2-c^2-2ab\right)\left(a^2+b^2-c^2+2ab\right)\)

\(M=\left(\left(a^2-2ab+b^2\right)-c^2\right)\left(\left(a^2+2ab+b^2\right)-c^2\right)\)

\(M=\left(\left(a-b\right)^2-c^2\right)\left(\left(a+b\right)^2-c^2\right)\)

\(M=\left(a-b-c\right)\left(a-b+c\right)\left(a+b-c\right)\left(a+b+c\right)\)