nBaCO3=\(\frac{7,88}{197}\)=0,04(mol)
nBa(OH)2=0,4.0,15=0,6(mol)
Bảo toàn Ba: nBa(HCO3)2=0,06-0,04=0,02(mol)
Bảo toàn C: nCO2=0,04+0,02.2=0,08(mol)
FeCO3\(\rightarrow\)FeO+CO2
\(\rightarrow\)nFeCO3=0,08(mol)
nFe2O3=\(\frac{30,4}{160}\)=0,19(mol)
nFe=0,19.2=0,38(mol)
\(\rightarrow\) nFe trong FexOy=0,3(mol)
mFexOy=23,2(g)
\(\rightarrow\)MFexOy=23,2:0,3/x=232x/3
x=3\(\rightarrow\)MFexOy=232\(\rightarrow\) CTHH là Fe3O4