nCuSO4 = \(\dfrac{32.10}{160.100}\)=0,02 mol
a,PTHH
Zn + CuSO4 --------> ZnSO4 + Cu Phản ứng oxi hóa khử
0,02-----0,02-----------0,02-------0,02mol
b,mZn= 0,02.65=1,l3 gam
c, mCu = 0,02.64= 1,28 gam
mZnSO4 = 0,02.161=3,22g
mdd= 1,13+ 32-1,28=31,85 gam
C% ZnSO4 = \(\dfrac{mct}{mdd}\).100 =\(\dfrac{3,22}{31,85}\).100 \(\approx\)10,11%