Vì đèn sáng bình thường nên : \(U_{\text{đ}\text{èn}}=U_{\text{đ}m};I_{\text{đ}\text{èn}}=I_{\text{đ}m};P_{\text{đ}\text{èn}}=P_{\text{đ}m}\)
ta có :
\(U_{m\text{ỗi}-\text{đ}\text{èn}}=\dfrac{240}{40}=6\left(V\right)\)
\(P_{m\text{ỗi}-\text{đ}\text{èn}}=\dfrac{40}{40}=1W\)
\(I_{m\text{ỗi}-\text{đ}\text{èn}}=\dfrac{P}{U}=\dfrac{1}{6}\left(A\right)\)