Question

Mn giúp em với;-;

Answer 1

b: \(=\dfrac{6m^2+11m+4}{\left(m-1\right)\left(m^2+m+1\right)}+\dfrac{2m-1}{m^2+m+1}-\dfrac{7}{m-1}\)

\(=\dfrac{6m^2+11m+4+2m^2-2m-m+1-7m^2-7m-7}{\left(m-1\right)\left(m^2+m+1\right)}\)

\(=\dfrac{m^2+m-2}{\left(m-1\right)\left(m^2+m+1\right)}\)

\(=\dfrac{m+2}{m^2+m+1}\)