1) a) \(\sqrt{1-6x+9x^2}+\sqrt{9x^2-12x+4}=\sqrt{\left(1-3x\right)^2}+\sqrt{\left(3x-2\right)^2}\)
\(=\left|1-3x\right|+\left|3x-2\right|\ge\left|1-3x+3x-2\right|=1\)
Vậy: GTNN là 1 khi \(\dfrac{1}{3}\le x\le\dfrac{2}{3}\)
b) Tương tự
2) Không rõ