`@` `\text {Ans}`
`\downarrow`
`250 - (x+20) \div 2 = 85`
`(x + 20) \div 2 = 250 - 85`
`(x + 20) \div 2 = 165`
`x +20 = 165 \times 2`
`x + 20 = 330`
`x = 330 - 20`
`x = 310`
Vậy, `x = 310.`
\(250-\left(x+20\right):2=85\)
\(\left(x+20\right):2=250-85\)
\(\left(x+20\right):2=165\)
\(x+20=165\times2\)
\(x+20=330\)
\(x=330-20\)
\(x=310\)
250 - (x+20) : 2= 85
<=> (x+20):2= 250-85
<=> (x+20)=( 250 - 85) x 2
<=> x+20= 165 x 2= 330
<=>x= 330-20=310