|x + 2| - 5 = 2018
⇔ |x + 2| = 2018 + 5
⇔ |x + 2| = 2023
⇔ \(\left[{}\begin{matrix}x+2=2023\\x+2=-2023\end{matrix}\right.\)
⇔ \(\left[{}\begin{matrix}x=2023-2\\x=-2023-2\end{matrix}\right.\)
⇔ \(\left[{}\begin{matrix}x=2021\\x=-2025\end{matrix}\right.\)
Vậy x ∈ \(\left\{2021;-2025\right\}\)
52018. (-2.3x)=52020
Tìm x để x+2là số nguyên dương
|-2017|+12018(|-2018|+20160)
\(|\)x-2018\(|\)=2018-x
Tìm x ∈ Z, biết:
\(|\)x-2018\(|\)=2018-x
A=[x-1]+(-2018)
S = 1-2+3-4+...+2007-2018
24. Tìm x∈Z biết:
a) ( x + 1) + ( x + 3) + ( x + 5 ) + …+ ( x + 99) = 0
b) ( x – 3) + ( x - 2) + ( x – 1 ) + …+ 10 + 11 = 11
c) x+(x+1)+(x+2)+...+2018+2019=2019
Mn ơi giúp mk vs mk cần gấp nka
Tìm x biết .
\(\dfrac{x+5}{2017}+\dfrac{x+4}{2018}+\dfrac{x+3}{2019}=-3\)
Mn ai bt thì giúp nka mk cảm ơn trc
