\(\left(\dfrac{1}{9}\right)^{2005}.9^{2005}-96^2:24^2=\left(\left(\dfrac{1}{9}\right)^{2005}.9^{2005}\right)-\left(96^2:24^2\right)\)
\(=\left(\dfrac{1^{2005}}{9^{2005}}.9^{2005}\right)-\left(96^2:24^2\right)=\left(1^{2005}\right)-\left(\left(4.24\right)^2:24^2\right)\)
\(=1-\left(4^2\right)=1-16=-15\)