\(\left\{{}\begin{matrix}2\left(x+1\right)-5\left(y+1\right)=8\\3\left(x+1\right)-2\left(y+1\right)=1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x+2-5y-5=8\\3x+3-2y-2=1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x-5y=11\\3x-2y=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}6x-15y=33\\6x-4y=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}-11y=33\\2x-5y=11\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}y=-3\\x=-2\end{matrix}\right.\)
Vậy ...
