Giải:
\(\left(6-4\dfrac{1}{2}\right):0,03+\left(3\dfrac{1}{20}-2,65\right):4+\dfrac{2}{5}\)
\(=\left(6-\dfrac{9}{2}\right).\dfrac{100}{3}+\left(\dfrac{61}{20}-\dfrac{53}{20}\right).\dfrac{1}{4}+\dfrac{2}{5}\)
\(=\dfrac{3}{2}.\dfrac{100}{3}+\dfrac{8}{20}.\dfrac{1}{4}+\dfrac{2}{5}\)
\(=50+\dfrac{1}{10}+\dfrac{2}{5}\)
\(=\dfrac{101}{2}=50,5\)
Vậy ...
\(\left(6-4\dfrac{1}{2}\right):0,03+\left(3\dfrac{1}{20}-2,65\right):4+\dfrac{2}{5}\)
\(=\left(\dfrac{12}{2}-\dfrac{9}{2}\right):\dfrac{3}{100}+\left(\dfrac{61}{20}-\dfrac{53}{20}\right).\dfrac{1}{4}+\dfrac{2}{5}\)
\(=\dfrac{3}{2}.\dfrac{100}{3}+\dfrac{8}{20}.\dfrac{1}{4}+\dfrac{2}{5}\)
\(=\dfrac{100}{2}+\dfrac{2}{20}+\dfrac{2}{5}\)
\(=\dfrac{1000}{20}+\dfrac{2}{20}+\dfrac{8}{20}\)
\(=\dfrac{1010}{2}=\dfrac{101}{2}\)
= ( 6 - 9/2 ) : 0,03 + ( 61/20 - 265/100 ) : 4 + 2/5
= 3/2 : 0,03 + 40/100 : 4 + 2/5
= 50 + 1/10 + 2/5
= 501/10 + 2/5
= 101/2
