\(n_{Al}=\dfrac{1,35}{27}=0,05\left(mol\right)\)
\(n_{CuSO_4}=0,4.0,27=0,108\left(mol\right)\)
PTHH: 2Al + 3CuSO4 --> Al2(SO4)3 + 3Cu
_____0,05-->0,075------>0,025
=> \(\left\{{}\begin{matrix}C_{M\left(Al_2\left(SO_4\right)_3\right)}=\dfrac{0,025}{0,4}=0,0625M\\C_{M\left(CuSO_4\right)}=\dfrac{0,108-0,075}{0,4}=0,0825M\end{matrix}\right.\)