a) ta có : \(tan83-cot7=\dfrac{sin83}{cos83}-\dfrac{cos7}{sin7}=\dfrac{sin83}{cos83}-\dfrac{sin83}{cos83}=0\)
b) ta có : \(tana+cota=3\Leftrightarrow\dfrac{sina}{cosa}+\dfrac{cosa}{sina}=3\)
\(\Leftrightarrow\dfrac{sin^2a+cos^2a}{sina.cosa}=3\Leftrightarrow\dfrac{1}{sina.cosa}=3\Leftrightarrow sina.cosa=\dfrac{1}{3}\)