lấy A(2;3) thuộc (d1)
Vì (d1)//(d2) nên \(d\left(\left(d1\right);\left(d2\right)\right)=d\left(A;\left(d2\right)\right)\)
=>\(d\left(\left(d1\right);\left(d2\right)\right)=\dfrac{\left|2\cdot6+3\cdot\left(-8\right)-13\right|}{\sqrt{6^2+\left(-8\right)^2}}=\dfrac{5}{2}\)