Ta có nCl2 = \(\dfrac{1,4}{22,4}\) = 0,0625 ( mol )
Fe + Cl2 \(\rightarrow\) FeCl2
x.........x...........x
Cu + Cl2 \(\rightarrow\) CuCl2
y.........y...........y
=> \(\left\{{}\begin{matrix}x+y=0,0625\\56x+64y=30\end{matrix}\right.\)
=> \(\left\{{}\begin{matrix}x=-3,25\\y=3,3125\end{matrix}\right.\)
Hình như đề sai bạn ơi