Ta có: \(n_{CaCO_3}=\dfrac{10}{100}=0,1\left(mol\right)\)
PT: \(CO_2+Ca\left(OH\right)_2\rightarrow CaCO_3+H_2O\)
Theo PT: \(n_{CO_2}=n_{CaCO_3}=0,1\left(mol\right)\)
\(n_{hh}=\dfrac{6,72}{22,4}=0,3\left(mol\right)\)
% số mol cũng là % thể tích.
\(\Rightarrow\left\{{}\begin{matrix}\%V_{CO_2}=\dfrac{0,1}{0,3}.100\%\approx33,33\%\\\%V_{CO}\approx66,67\%\end{matrix}\right.\)