Đề này là Toán chứ nhỉ!?
a) (x + 1)3 = x3 + 3x2 + 3x + 1
b) (2x + 3)3 = 8x3 + 36x2 + 54x + 27
c) \(\left(x+\frac{1}{2}\right)^3=\) \(x^3+\frac{3x^2}{2}+\frac{3x}{4}+\frac{1}{8}\)
d) (x2 + 2)3 = x6 + 6x4 + 12x2 + 8
e) (2x + 3y)3 = 8x3 + 36x2y + 54xy2 + 27y3
f) \(\left(\frac{1}{2}x+y^2\right)^3=\frac{x^3}{8}+\frac{3x^2y^2}{4}+\frac{3xy^4}{2}+y^6\)