a) \(\int_{\dfrac{\pi}{8}}^{\dfrac{2\pi}{8}}\)\(\dfrac{dx}{sin^2xcos^2x}\)
b) \(\int_{\dfrac{\pi}{6}}^{\dfrac{\pi}{3}}\)\(\dfrac{cos2xdx}{sin^2xcos^2x}\)
c) \(\int_0^{\dfrac{\pi}{3}}\)\(\dfrac{cos3x}{cosx}\)dx
Cho \(\int_0^4f\left(x\right)dx=2018\)Giá trị \(\int_0^2f\left(2x\right)dx+\int_{-2}^2\text{}f\left(2-x\right)dx\)bằng
A. 4036
B. 3027
C. 0
D. -1009
\(\int\limits^{\frac{Π}{2}}_{\frac{Π}{6}}\frac{1+SIN2x+cOS2x}{sINx+cosx}dx\)
\(\int_{-1}^0\) \(\dfrac{x^2-4x+4}{x^2-1}dx\)
\(\int_{-1}^0\)\(\dfrac{3x^2+3x+3}{x^3-3x+2}dx\)
\(\int_{-1}^0\)\(\dfrac{4x+4}{\left(x^2-4x+3\right)^2}dx\)
\(\int_{\dfrac{\pi}{4}}^{\dfrac{\pi}{3}}\)\(\dfrac{cos2x}{sin^2x}dx\)
\(\int_{\dfrac{\pi}{4}}^{\dfrac{\pi}{3}}\)\(\dfrac{2cos2x+5}{sin^2x}dx\)
tính tích phân :
\(A=\int_{-1}^0\frac{\left(x^2-1\right)}{\left(x^2+1\right)^2}dx\)
(giải giúp mình với )