Câu 1:
\(y'=\dfrac{\left(x^2-3x+5\right)'\left(x^2-1\right)-\left(x^2-3x+5\right)\left(x^2-1\right)'}{\left(x^2-1\right)^2}\)
\(=\dfrac{\left(2x-3\right)\left(x^2-1\right)-2x\left(x^2-3x+5\right)}{\left(x^2-1\right)^2}\)
\(=\dfrac{2x^3-2x-3x^2+3-2x^3+6x^2-10x}{\left(x^2-1\right)^2}\)
\(=\dfrac{3x^2-12x}{\left(x^2-1\right)^2}\)
Đúng 1
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