nNaOH= 0.1*0.2=0.02 mol
CH3COOH + NaOH --> CH3COONa + H2O
=> nCH3COOH= 0.02 mol
mCH3COOH= 1.2g
nH2= 0.336/22.4=0.015 mol
CH3COOH + Na --> CH3COONa + 1/2H2 (1)
C2H5OH + Na --> C2H5ONa + 1/2 H2
nH2(1)= 0.01 mol
nH2(2)= 0.015-0.01=0.005 mol
=> nC2H5OH= 0.01 mol
mC2H5OH= 0.46g
mX= mCH3COOH + mC2H5OH= 1.12+0.46=1.58g