Question

hoàn thành sơđồ chuyển hoá sau bằng các viết các phương trình hoá học

H2C4--->C2H5OH--->CH3COOH--->CH3COONa--->CH4

Answer 1

(1) C2H4 + H2O → C2H5OH (axit ,t\(^o\) )

(2) C2H5OH + O2 → CH3COOH + H2O (men giấm ,t\(^o\))

(3) CH3COOH + Na → CH3COONa + 1/2H\(_2\)

(4) CH3COONa + NaOH → CH4 + Na2CO3 (CaO ,t\(^o\))

Answer 2

\(\left(1\right)C_2H_4+H_2O\underrightarrow{axit}C_2H_5OH\)

\(\left(2\right)C_2H_5OH +O_2\xrightarrow[t^o]{mengiam}CH_3COOH+H_2O\)

\(\left(3\right)CH_3COOH+Na\rightarrow CH_3COONa+\frac{1}{2}H_2\uparrow\)

\(\left(4\right)CH_3COONa+NaOH\xrightarrow[t^o]{CaO}CH_4+Na_2CO_3\)

Answer 3

C2H4 + H2O -axit-> C2H5OH

C2H5OH + O2 -mg-> CH3COOH + H2O

CH3COOH + NaOH --> CH3COONa + H2O

CH3COONa + NaOH -CaO,to-> Na2CO3 + CH4

Answer 4

C2H4 ạ mình viết lộn