\(n_{NaOH}=\dfrac{60}{40}=1,5mol\)
\(\Rightarrow C_{MddNaOH}=\dfrac{1,5}{0,5}=3M\)
Đổi : \(500ml=0,5l\)
Ta có \(n_{NaOH}=\dfrac{60}{40}=1,5\left(mol\right)\)
\(\Rightarrow C_{M_{ddNaOH}}=\dfrac{1,5}{0,5}=3\left(M\right)\)
200ml = 0.5l
nNaOH=60/40=1.5mol
CM = n/v = 1.5/0.5= 3M