\(n_{Zn}=\dfrac{13}{65}=0,2\left(mol\right)\)
\(Zn+2HCl\rightarrow ZnCl_2+H_2\)
0,2 0,4 0,2 ( mol )
\(m_{ZnCl_2}=0,2.136=27,2\left(g\right)\)
\(C_{M_{HCl}}=\dfrac{0,4}{0,2}=2\left(M\right)\)
\(n_{Zn}=\dfrac{13}{65}=0,2mol\)
PTHH: \(Zn+2HCl->ZnCl_2+H_2\)
a/ \(n_{H_2}=n_{Zn}=0,2mol\)
\(=>V=0,2.22,4=4,48\left(L\right)\)
b/ \(n_{Zn}=n_{ZnCl2}=0,2mol\)
\(m_{muối}=m_{ZnCl_2}=0,2\left(65+35,5.2\right)=27,2g\)
c/ \(n_{HCl}=2n_{H_2}=0,2.2=0,4mol\)
\(C_{M\left(HCl\right)}=\dfrac{0.4}{0,2}=2\left(M\right)\)