\(m_{muoi}=m_{Kl}-m_{goc.NO3^-}\)
\(\Rightarrow m_{goc.NO3^-}=116-19=97\left(g\right)\)
\(\Rightarrow n_{NO3}=\frac{97}{62}\left(mol\right)\)
\(n_{HNO3}=n_{e.nhan}+n_{tao.khi}=n_{goc.NH3^-}+n_{tao.khi}\)
\(\Rightarrow n_{HN3}=\frac{97}{62}+0,08.2+0,1=\frac{1414}{775}\left(mol\right)\)
\(\Rightarrow m_{HNO3}=\frac{1414}{775.63}=114,95\left(g\right)\)