Question

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Answer 1

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Answer 2

Ta có : \(\frac{x}{2}=\frac{y}{4}\Rightarrow x=2k;y=4k\left(k\in Z\right)\) Thay vào P ta được :

\(P=\frac{7\left(2k\right)^2+3\left(4k\right)^2}{14\left(2k\right)^2-3\left(4k\right)^2}=\frac{7.4.k^2+3.16.k^2}{14.4.k^2-3.16.k^2}=\frac{4k^2\left(7+3.4\right)}{4k^2\left(14-3.4\right)}=\frac{7+12}{14-12}=\frac{19}{2}\)

Vậy \(P=\frac{19}{2}\)