Ta có: 2^2+2^2=2^3
2^3+2^3=2^4
...
=> 2^2+2^2+2^3+2^4+...+2^1975
= 2^3+2^3+2^4+...+2^1975
...
Cứ thế tiếp tục, ta sẽ có: 2^1974+2^1974+2^1975
= 2^1975+2^1975
= 2^1976
Chúc bạn học tốt!
Đặt tổng A.
Ta có :
A = \(2^2+2^2+2^3+2^4+....+2^{1975}\)
\(\Rightarrow2A=2^2.2+2^2.2+2^3.2+2^4.2+...+2^{1975}.2\)
\(\Rightarrow2A=2\left(1+2+2^2+2^3+2^4+...+2^{1975}\right)\)
\(\Rightarrow2A=2+2^2+2^3+....+2^{1976}\)
\(\Rightarrow S=1+2+2^2+...+2^{1974}\)
\(\Rightarrow S=2^{1975}-1\)