Question

Hãy phân tích các số A, B ra thừa số nguyên tố:
A = \(4^2.6^3\)
B =\(9^2.15^2\)

Answer 1

A= \(4^2.6^3= 4.4.6.6.6\)

\(=(2^2).(2^2).(2.3).(2.3).(2.3)\)

\(=2^{2+2+1+1+1}.3^{1+1+1}=2^7.3^3\)

B =\(9^2.15^2\)

\(=9.9.15.15\)

\(=3^2.3^2.3.5.3.5\)

\(=3^{2+2+1+1}.5^{1+1}\)

=\(3^6.5^2\)

Answer 2

A= 4 2 .6 3 = 4.4.6.6.6 = ( 2 2 ) . ( 2 2 ) . ( 2.3 ) . ( 2.3 ) . ( 2.3 ) = 2 2 + 2 + 1 + 1 + 1 .3 1 + 1 + 1 = 2 7 .3 3 B = 9 2 .15 2 = 9.9.15.15 = 3 2 .3 2 .3 .5 .3 .5 = 3 2 + 2 + 1 + 1 .5 1 + 1 = 3 6 .5 2

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