Pythagorean theorem: \(AD=\sqrt{BD^2-AB^2}=4\) (cm)
\(\Rightarrow BC=AD=4\left(cm\right)\)
\(CC'=\sqrt{BC'^2-BC^2}=4\sqrt{2}\)
The lateral surface area: \(2CC'.\left(BC+AB\right)=56\sqrt{2}\left(cm^2\right)\)
A rectangular garden has length of x ( dm ) and area of 252 dm2. If the width is 5 dm less than one - third of the length, then the perimeter of this garden is ... dm
Half of the perimeter of a rectangular school yard is 0.24km. The width is of the length. Find the area of the yard in square meters?
Giai bang TA ho minh nhe
A box contains 50 blue square cards whose the side length are 2 cm, 4 cm, 6 cm, ..., 100 cm, respectively and 50 red square cards with side lengths are 1 cm, 3 cm, 5 cm, ..., 99 cm, respectively. The total area of the blue cards is greater than the total area of the red care is .... cm2
Given that ABCD is a rectangle with AB = 12 cm, AD = 6 cm. M and N are respectively midpoint of segments BC and CD. Find the area of triangle AMN in square centimeters.
Let ABCD be a trapezoid with bases AB, CD and O be the intersection of AC and BD. If the areas of triangle OAB, triangle OCD are 16cm2, 40cm2respectively and M is the midpoint of BD, then the area of the triangle AMD is .........cm2.
Let ABC be an isoceles triangle (AB = AC) and its area is 501cm2. BD is the internal bisector of the angle ABC (D ∈ AC), E is a point on the opposite ray of CA such that CE = CB. I is a point on BC such that CI = 1/2 BI. The line EI meets AB at K, BD meets KC at H. Find the area of the triangle AHC.
What is the maximum possible area, in , of a rectangle with a perimeter of 20cm?
A trapezuim ABCD has two parallel sides AB and CD. The diagonals AC and BD intersect at E. If the areas of triangle CDE and CDB are 1 and 4 respectively, what is the area of the trapezuim ABCD
