\(m_{Na}=\dfrac{106.43,4}{100}=46,004\approx46g\)
\(m_C=\dfrac{106.11,32}{100}=11,9992\approx12g\)
\(m_O=106-46-12=48g\)
\(n_{Na}=\dfrac{46}{23}=2mol\)
\(n_C=\dfrac{12}{12}=1mol\)
\(n_O=\dfrac{48}{16}=3mol\)
\(\Rightarrow CTHH:Na_2CO_3\)
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