Question

. Giúp mình chuẩn bị thi

(1+\(\dfrac{1}{100}\)). (1+\(\dfrac{1}{101}\)).(1+\(\dfrac{1}{102}\))....(1+\(\dfrac{1}{2018}\))

Answer 1

(1+\(\dfrac{1}{100}\)) . (1+\(\dfrac{1}{101}\)) . (1+\(\dfrac{1}{102}\)) ... (1+\(\dfrac{1}{2018}\))

= \(\dfrac{101}{100}\).\(\dfrac{102}{101}\).\(\dfrac{103}{102}\)... \(\dfrac{2018}{2017}\). \(\dfrac{2019}{2018}\)

= \(\dfrac{2019}{100}\)

Answer 2

\(\left(1+\dfrac{1}{100}\right).\left(1+\dfrac{1}{101}\right).\left(1+\dfrac{1}{102}\right)....\left(1+\dfrac{1}{2018}\right)=\dfrac{101}{100}.\dfrac{102}{101}.\dfrac{103}{102}...\dfrac{2019}{2018}=\dfrac{2019}{100}\)

Answer 3

\(=\dfrac{101}{100}.\dfrac{102}{101}.....\dfrac{2019}{2018}\)

\(=\dfrac{2019}{100}\)