Question

giúp mình câu 1

Answer 1

Bài 1:

a: \(P=\frac{4}{x+2}-\frac{3}{2-x}+\frac{-5x-2}{x^2-4}\)

\(=\frac{4}{x+2}+\frac{3}{x-2}+\frac{-5x-2}{\left(x-2\right)\left(x+2\right)}=\frac{4x-8+3x+6-5x-2}{\left(x-2\right)\left(x+2\right)}\)

\(=\frac{2x-4}{\left(x-2\right)\left(x+2\right)}=\frac{2\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}=\frac{2}{x+2}\)

b: Để P nguyên thì 2⋮x+2

=>x+2∈{1;-1;2;-2}

=>x∈{-1;-3;0;-4}