\(=\left(\dfrac{15}{6}-\dfrac{18}{6}\right)^2+\dfrac{1}{6}+\dfrac{4}{3}=\left(\dfrac{-3}{6}\right)^2+\dfrac{1}{6}+\dfrac{8}{6}=\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{8}{6}=\dfrac{3}{6}+\dfrac{1}{6}+\dfrac{8}{6}=2\)
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