Ta có: \(\frac{\frac{2}{11}-\frac{2}{13}+\frac{2}{17}}{\frac{5}{11}-\frac{5}{13}+\frac{5}{17}}=\frac{2\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{17}\right)}{5\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{17}\right)}=\frac{2}{5}\)
\(\frac{\frac{2}{11}-\frac{2}{13}+\frac{2}{17}}{\frac{5}{11}-\frac{5}{13}+\frac{5}{17}}\)
\(=\frac{2\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{17}\right)}{5\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{17}\right)}\)
=\(\frac{2}{5}\)
\(=\frac{2.\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{17}\right)}{5.\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{17}\right)}=\frac{2}{5}\)
\(\frac{\frac{2}{11}-\frac{2}{13}+\frac{2}{17}}{\frac{5}{11}-\frac{5}{13}+\frac{5}{17}}=\frac{2.\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{17}\right)}{5.\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{17}\right)}=\frac{2}{5}\)