Question

Giúp em với ạ

Answer 1

vì R nt R₁ => I_r = I₁ = I = I_A = 5A

U_r = U_v = 4V

=> R= \(\dfrac{U_r}{I_r}\) = \(\dfrac{4}{5}\) = 0,8 Ω

vì R nt R₁ => U₁= U - U_r = 9 - 4 = 5V

=> R₁= \(\dfrac{U_1}{I_1}\) = 1Ω

b/ vì R nt R₂ => I₂ = I_r = \(\dfrac{U_r}{R}\) = \(\dfrac{U_v}{r}\) = \(\dfrac{2}{0,8}\)= 2,5 A

U₂=U - U_r = 9 - 2 = 7V

R₂ = \(\dfrac{U_2}{I_2}\) = \(\dfrac{7}{2,5}\) = 2,8Ω

Answer 2

u-9