\(\dfrac{15-x}{7}=\dfrac{x+7}{4}\)
\(\Leftrightarrow4\left(15-x\right)=7\left(x+7\right)\)
\(\Leftrightarrow60-4x=7x+49\)
\(\Rightarrow7x+4x=60-49\)
\(\Rightarrow11x=11\)
\(\Rightarrow x=\dfrac{11}{11}\)
\(\Rightarrow x=1\)
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\(\dfrac{15-x}{7}=\dfrac{x+7}{4}\\ \Rightarrow\left(15-x\right)\cdot4=\left(x+7\right)\cdot7\\ \Rightarrow60-4x=7x+49\\ \Rightarrow-4x-7x=49-60\\ \Rightarrow-11x=-11\\ \Rightarrow x=1\)
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