\(pt \Leftrightarrow x^3-3x^2+3x-1+8x^3+36x^2+54x+27=27x^3+8\)
\(\Leftrightarrow 18x^3-33x^2-57x-18=0\)
\(\Leftrightarrow (3x+2)(6x^2-15x-9)=0\)
\(\Leftrightarrow 3(3x+2)(2x+1)(x-3)=0\)
\(\Leftrightarrow x\in\{\dfrac{-1}{2},\dfrac{-2}{3},3\}\)
\(pt \Leftrightarrow x^3-3x^2+3x-1+8x^3+36x^2+54x+27=27x^3+8\)
\(\Leftrightarrow 18x^3-33x^2-57x-18=0\)
\(\Leftrightarrow (3x+2)(6x^2-15x-9)=0\)
\(\Leftrightarrow 3(3x+2)(2x+1)(x-3)=0\)
\(\Leftrightarrow x\in\{\dfrac{-1}{2},\dfrac{-2}{3},3\}\)
14, giải các PT sau.
1, 4-(x-5)=5(x-3x)
2, 32-4(0,5y-5)=3y+2
3, 19-2(x+11)=5(2x-3)-4(5x-7)
4, 4(x+3)-7x+17=8(5x-1)+166
5, 17-14(x+1)=13-4(x+1)-5(x-3)
6, 5(x+10)2+2x=5x2-3
7, (2x-1)2+5=(2x+3)(2x-3)-x
8, 3(x-2)2+2(x+3)(x-3)=5(x+1)2
14, giải các PT sau.
1, 4-(x-5)=5(x-3x)
2, 32-4(0,5y-5)=3y+2
3, 19-2(x+11)=5(2x-3)-4(5x-7)
4, 4(x+3)-7x+17=8(5x-1)+166
5, 17-14(x+1)=13-4(x+1)-5(x-3)
6, 5(x+10)2+2x=5x2-3
7, (2x-1)2+5=(2x+3)(2x-3)-x
8, 3(x-2)2+2(x+3)(x-3)=5(x+1)2
Cho pt : 2x – 3 =0 (1) và (a - 1)x = x - 5. (2)
a/ Giải pt (1)
b/ Tìm a để pt (1) và Pt (2) tương đương.
giải các pt sau
a,2x(x-7)-(x-1)2 -x2 +7
b,x(x+3)2 -3x = (x+2)3 +1
c, 2(x-1)2 +(x+3)3=3(x-2)(x+1)
Giải pt sau:
a) \(\left(\dfrac{8}{1.9}+\dfrac{8}{9.17}+\dfrac{8}{17.25}+....+\dfrac{8}{49.57}\right)+2.\left(x-1\right)=\dfrac{2x+7}{3}+\dfrac{5x-8}{4}\)
b) \(\left(x+2\right).\left(x-2\right).\left(x^2-10\right)=72\)
c) (x+3)4+ (x+5)4 = 2
giải phương trình sau
1. (2x-3)(2x+3)-4(x+5)^2= -9(1+5x)
2. 2x(x+5)=(x+3)^2+(x-1)^2+20
3.(x+2)^3-(x-2)^3=12x(x-1)-8
Giải các pt sau:
a. -\(\frac{5}{9}\)x +1=\(\frac{2}{3}\)x - 10
b. \(\frac{x-22}{8}+\frac{x-21}{9}+\frac{x-20}{10}+\frac{x-19}{11}=4\)
c. ( 5x +3)(x2 + 4 )(x - 4) = 0
d. ( 2x - 1)2 + ( 2 - x )( 2x - 1) = 0
Giải pt:
a) \(\frac{^{x^2+2x-16}}{x^2-x-12}+1=\frac{2x+1}{x+3}+\frac{3x-8}{x-4}\)
b) \(\frac{2x-1}{x+2}+\frac{7x+9}{\left(x+2\right)\left(x-1\right)}=\frac{3x-1}{x-1}\)
c) \(\frac{x+1}{20}+\frac{x+2}{19}+\frac{x+3}{18}=\frac{x+20}{1}+\frac{x+19}{2}+\frac{x+18}{3}\)
Giải pt bằng phương pháp đặt ẩn phụ
a,\(\left(x^2+2x+3\right)\left(x^2+2x+1\right)=3\)
b,\(x\left(x-1\right)\left(x^2-x+1\right)-6=0\)