x3 + (2x - 1)3 = (3x - 1)3
⇔ (3x - 1)[ x2 - x(2x - 1) + 4x2 - 4x + 1] = (3x - 1)3
⇔ x2- 2x2 + x + 4x2 - 4x + 1 = (3x - 1)2
⇔ 3x2 - 3x + 1 = 9x2 - 6x + 1
⇔ 6x2 - 3x = 0
⇔3x(2x - 1) = 0
⇔ \(\left[{}\begin{matrix}3x=0\\2x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\frac{1}{2}\end{matrix}\right.\)
Vậy nghiệm của pt là x = 0; x = \(\frac{1}{2}\)