ta có \(\left(x+\frac{1}{3}\right)^2-2.5.\left(x+\frac{1}{3}\right)+5^2-16=0\)
⇔ \(\left(x+\frac{1}{3}-5\right)^2-4^2=0\)
⇔ \(\left(x+\frac{1}{3}-5-4\right).\left(x+\frac{1}{3}-5+4\right)=0\)
⇔ \(\left[{}\begin{matrix}x=\frac{-26}{3}\\x=\frac{-2}{3}\end{matrix}\right.\)