Sửa đề: \(\sqrt{x-5}+\dfrac{1}{3}\sqrt{9x-45}=\dfrac{1}{5}\sqrt{25x-125}+6\)
\(\Leftrightarrow\sqrt{x-5}+\dfrac{1}{3}\cdot3\cdot\sqrt{x-5}-\dfrac{1}{5}\cdot5\sqrt{x-5}=6\)
\(\Leftrightarrow\sqrt{x-5}=6\)
=>x-5=36
hay x=41
giai pt
\(\sqrt{x-5}+\dfrac{1}{3}\sqrt{9x-45}=\dfrac{1}{5}\sqrt{25-125+6}\)
cho phuong trinh:\(\dfrac{2+\sqrt{x}}{\sqrt{2}+\sqrt{2+\sqrt{x}}}+\dfrac{2-\sqrt{x}}{\sqrt{2}-\sqrt{2-\sqrt{x}}}=\sqrt{2}\)
a/tim dieu kien cua x de phuong trinh co nghia
b/giai phuong trinh
giai phuong trinh \(\sqrt{x^2-2x+1}+\sqrt{x^2-4x+4}=\sqrt{1+2005^2+\dfrac{2005^2}{2006^2}}+\dfrac{2005}{2006}\)
\(\sqrt{4x-20}\)+\(\sqrt{x-5}\)-\(\dfrac{1}{3}\)\(\sqrt{9x-45}\)
Giải các phương trình sau:
a)\(\sqrt{3x+1}=\sqrt{4x-3}\)
b)\(\sqrt{9x+18}-5\sqrt{x+2}+\dfrac{4}{5}\sqrt{25x+50}=6\)
Giải PT:
a) \(\dfrac{9x-7}{\sqrt{7x+5}}=\sqrt{7x+5}.\)
b) \(\sqrt{4x-20}+3\sqrt{\dfrac{x-5}{9}}-\dfrac{1}{3}\sqrt{9x-45}=4.\)
c) \(2x-x^2+\sqrt{6x^2-12x+7}=0.\)
d) \(\left(x+1\right)\left(x+4\right)-3\sqrt{x^2+5x+2}=6.\)
giải phương trình
a)\(\dfrac{\sqrt{x}-2}{\sqrt{x}-4}=\dfrac{\sqrt{x}-6}{\sqrt{x}-7}\)
b)\(2+\sqrt[3]{x+5}=0\)
c)0,5\(\sqrt{\dfrac{2}{x}}-\sqrt{\dfrac{8}{25x}}+\sqrt{\dfrac{1}{4x}}=\dfrac{1}{5}\)
\(\sqrt{\dfrac{x+2}{4}}+\sqrt{25x+50}-2\sqrt{x+2}=14\) ; \(\sqrt{2x+3}=x\) ; \(\sqrt{25x^2+20x+4}=1\) ; \(\sqrt{\dfrac{x+1}{2x-1}}=2\) ; \(\dfrac{\sqrt{x-2}}{\sqrt{3x+1}}=6\)
Tìm x
1/ giai phuong trinh : \(\sqrt{\dfrac{2x+2}{x+2}}-\sqrt{\dfrac{x+2}{2x+2}}=\dfrac{7}{12}\)
2/ cho tam giac ABC vuong tai A, phan giac AD;AE.
a/ chung minh \(\dfrac{\sqrt{2}}{AD}=\dfrac{1}{AB}+\dfrac{1}{AC}\)
b/ he thuc tren thay doi nhu the nao neu BAC=60o ? BAC=120o
c/ he thuc tren thay doi nhu the nao neu thay doi phan giac trong AD voi phan giac ngoai AE
