ĐKXĐ: \(x\ge1\)
\(\Leftrightarrow\sqrt{x-1}=\sqrt{5x-1}+\sqrt{3x-2}\)
\(\Leftrightarrow x-1=8x-3+2\sqrt{15x^2-13x+2}\)
\(\Leftrightarrow2-7x=2\sqrt{15x^2-13x+2}\)
Do \(x\le1\Rightarrow2-7x< 0\Rightarrow VP< 0\)
Mà \(VT>0\Rightarrow\) pt vô nghiệm