Question

Giải phương trình sau:

  

Answer 1

\(-\dfrac{1}{4}\left(x+4\right)+1=\dfrac{x}{4}+\dfrac{1}{2}\)

\(\Leftrightarrow-\dfrac{1}{4}x-1+1-\dfrac{x}{4}=\dfrac{1}{2}\)

\(\Leftrightarrow-\dfrac{x}{4}-\dfrac{x}{4}=\dfrac{1}{2}\)

\(\Leftrightarrow-\dfrac{2x}{4}=\dfrac{1}{2}\)

\(\Leftrightarrow-\dfrac{x}{2}=\dfrac{1}{2}\)

\(\Leftrightarrow x=-1\)

#Urushi

Answer 2

=>-1/4x-1+1=x/4+1/2

=>-1/4x-1/4x=1/2

=>-1/2x=1/2

=>x=-1